Potential improvement, 用1个loop, out of bound 用expression赋值0, 还有不需要用Integer value of 直接减一减就好了
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36 | public class Solution {
public String addBinary(String a, String b) {
if (a == null || a.equals("")) return b;
if (b == null || b.equals("")) return a;
int i = a.length()-1;
int j = b.length()-1;
int carry = 0;
String result = "";
while (i >= 0 && j >= 0){
int v1 = Integer.valueOf(a.charAt(i--)+"");
int v2 = Integer.valueOf(b.charAt(j--)+"");
int sum = (v1+v2+carry)%2;
carry = (v1+v2+carry)/2;
result = sum+result;
}
while (i>=0){
int v1 = Integer.valueOf(a.charAt(i--)+"");
int sum = (v1+carry)%2;
carry = (v1+carry)/2;
result = sum+result;
}
while (j>=0){
int v2 = Integer.valueOf(b.charAt(j--)+"");
int sum = (v2+carry)%2;
carry = (v2+carry)/2;
result = sum+result;
}
if (carry == 1){
result = "1"+result;
}
return result;
}
}
|
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