Saturday, November 14, 2015

[leetcode] Reorder List

某些地方写得不够短 例如loop里面可以一次接两个instead of 用个boolean来判断哪次接哪个
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/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
public class Solution {
    public void reorderList(ListNode head) {
        if (head == null || head.next == null) return;
        ListNode slow = head;
        ListNode fast = head;
        while (fast.next != null && fast.next.next != null){
            slow = slow.next;
            fast = fast.next.next;
        }
        ListNode list1 = head;
        ListNode mid = slow.next;
        slow.next = null;
        ListNode list2 = reverse(mid);
        boolean isList1 = true;
        ListNode dummy = new ListNode(-1);
        ListNode previous = dummy;
        while (list2 != null){
            if (isList1){
                previous.next = list1;
                list1 = list1.next;
            } else{
                previous.next = list2;
                list2 = list2.next;
            }
            previous = previous.next;
            isList1 = !isList1;
        }
        if (list1 != null){
            previous.next = list1;
        }
        return;
    }
    
    private ListNode reverse(ListNode root){
        if (root == null || root.next == null) return root;
        ListNode previous = root;
        ListNode current = root.next;
        previous.next = null;
        while (current != null){
            ListNode next = current.next;
            current.next = previous;
            previous = current;
            current = next;
        }
        
        return previous;
    }
}

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